> (Yes, the arrow operator accepts a scalar naming the method to call.)

Only half the truth, if $method is a code-ref it'll be called like a method (i.e. with $obj as first argument)

Sorry for nitpicking :)

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^2: $50 towards a laptop for the winner by LanX
in thread $50 towards a laptop for the winner by perlfan

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