> but I can't get back-references,

This works for me

  DB<44> $pat='(x)\1'

  DB<45> $mod='i'

  DB<46> 'xX' =~ /(?$mod)$pat/; say "$&:$1"
xX:x

  DB<47>

[download]

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^4: Regexp substitution using variables by LanX
in thread Regexp substitution using variables by MikeTaylor

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