Same approach, but as a one liner:

  
  DB<5> p
0123456789012345678901234567890123456789

  DB<5> x / @{[ '(....)' x4 ]} (.+) /x
0  0123
1  4567
2  8901
3  2345
4  678901234567890123456789
  DB<6>

[download]

Cheers Rolf
(addicted to the Perl Programming Language :)
Wikisyntax for the Monastery

In reply to Re^2: mysteries of regex substring matching by LanX
in thread mysteries of regex substring matching by smile4me

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