"g" always means "all the matches".

With s///g, it performs all the substitutions.

With m//g, it normally returns all the matches.

This is very similar.

I said "normally" because m//g in scalar context can't return all the matches without external help. That's why a loop needs to be introduced.

You're looking for

$x =~ s{ \s* (foo\w) \s* }{ push @captured, $1; "" }xeg;

In reply to Re: while-loop regex substitution with 'g' option by ikegami
in thread while-loop regex substitution with 'g' option by ibm1620

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