Update: The OP was completely changed while I wrote this reply, including the subject. OP below. My answer to the revised question further below.
Original post:
for some reason, i want to pass certain value in @array to the while loop, but my code only allows me to pass the first value. Below is the result i want to get, Can anyone help me out? T_T#!/usr/local/bin/perl use strict; use warnings; my $i=1; my @array = (34,543,754,5432,865,623,8635,5324,62,8654); my @list = (1, 3, 5, 8); foreach $a(@list){ print "foreach print value of a: $a\n"; while ($i) { print "while print value of a: $a\n"; $i=$i-1; print $array [$a], "\n"; } }
Original post ends hereforeach print value of a: 1 while print value of a: 1 543 foreach print value of a: 3 while print value of a: 3 5432 foreach print value of a: 5 while print value of a: 5 623 foreach print value of a: 8 while print value of a: 8 62
Use for:
my $value = $array[$_] for @list;
Output:#!/usr/bin/perl use strict; use warnings; use feature qw/ say /; use Data::Dumper; my @array = (34,543,754,5432,865,623,8635,5324,62,8654); my @list = (1, 3, 5, 8); say "\$a: $_ \$array[$_] $array[$_]" for @list; __END__
$ perl 1140597.pl $a: 1 $array[1] 543 $a: 3 $array[3] 5432 $a: 5 $array[5] 623 $a: 8 $array[8] 62 $
In reply to Re: not able to pass foreach value to a while loop
by 1nickt
in thread how to move to the first row of array after passing it through a while loop
by wangruonan
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