Take a closer look at how his code works. It keeps generating numbers until it has 10 unique numbers, then prints out a list of those 10 unique numbers. Even if a number has been chosen several times, it still counts as only one unique number and will only be printed once. Thus, no duplicates will appear in the output.

The main difference between his code and yours is that, if a number is selected three times, yours will have a value of 1 in the hash for that key, while his will have a value of 3. But, since the values are never used for anything (you just output the keys and ignore the values), it doesn't matter either way.

In reply to Re^4: Perl - Unique Numbers by dsheroh
in thread Perl - Unique Numbers by deelinux

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