IIRC these structures are called
multisets because some elements are repeated in one of your examples.
If I understand your requirements correctly, you can use your approach in a pragmatic way, because any "neighboring" multi sets must have at least 8 digits in common.
So
- Sort the 9 elements of the original multi set
- Calculate all distinct 8 element subsets (at most 9)
- Create hash keys by joining them
- push the original set into a HoA ( or HoH) for each subset.
At the end you'll only need 9 hash look ups to drastically narrow down potential candidates.
NB: That's a pragmatic approach, a detailed survey might show more efficient algorithms.
HTH :)
PS: this problem reminds me of hamming distance of error correcting codes, but I doubt you can easily apply this here.
update
I just realized that you already sketched that approach in Re^2: Finding Nearly Identical Sets . Not sure why you say it's ugly, cause a HoH should be quite fast, and you'd need to check anyway, if your input is equidistant to multiple neighbors.
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