foo($$); &foo($0);
From perlsub:

Not only does the & form make the argument list optional, it also disables any prototype checking on arguments you do provide. This is partly for historical reasons, and partly for having a convenient way to cheat if you know what you're doing

regards,
tomte

In reply to Re: ($$) and 1; by Tomte
in thread ($$) and 1; by Jaap

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