$a = \$b should set $a to be a reference of $b (a reference being an actual separate object), and $a := $b should set $a to be an alias of $b (an alias being only a name reference that is resolved at compile-time). I think thats the case, at least :) 


:^) # Fear the wrath of the hyper smiley!

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In reply to Re: Re: Perl6 - value vs. reference issues by jryan
in thread Perl6 - value vs. reference issues by John M. Dlugosz

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