my $strFoo = @_ evaluates @_ in scalar context. Arrays in scalar context return their size. What you want is my ($strFoo) = @_ which evaluates @_ in list context returning its values.

90% of every Perl application is already written. ⇒
dragonchild

In reply to Re: shift vs. @_ (where @_ evaluates to 1) by pfaut
in thread shift vs. @_ (where @_ evaluates to 1) by P0w3rK!d

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