Brute force here is at worst 10^5. But since digit3 depends on digit1, and digit5 depends on digit4 there are only three 'loose' digits, or 10^3 possibilities.
You could brute-froce the 1000 combinations on paper ;)
-jack
ps, you can find old Ecco columns by typing 'ecco' in the search box on ddj.
In reply to Re: Simple Math Puzzle...
by jackdied
in thread Simple Math Puzzle...
by Daruma
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |