Thanks Sir,

the $path =~ /^(\w):\\(^\\+)\\?/ worked for me, but what I don't understand how does it get the $2 value? There is no “.” or “\w” in the second parenthesis. Oh well, as long as it works…

In reply to Re: Re: filtering folder path using regex. by blackadder
in thread filtering folder path using regex. by blackadder

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