As everybody has already pointed out you're out of luck I'm afraid. Prototypes don't apply to methods. You'll just have to pass the subroutine explicitly like this:

$object->method( sub { ... } );

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(Note: you are actually passing a subroutine with the prototype too - it just looks like a block).

In reply to Re: Using "prototype" tricks in methods by adrianh
in thread Using "prototype" tricks in methods by v_thunder

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