but if we only allow either lower case or upper case (not both mixed), the problem nearly disappears:
As long as you can mix numbers with letters the problem remains.
or can you find a value for $z so that ++ $z is "0"? no, you can't.
What about -1?
But thanks, some good links there. :-)
In reply to Re: Re: Re: $a++ allowed by $a-- is not ! why?
by demerphq
in thread $a++ allowed by $a-- is not ! why?
by abhishes
| For: | Use: | ||
| & | & | ||
| < | < | ||
| > | > | ||
| [ | [ | ||
| ] | ] |