Just for grins, I calculated the odds...I think it's right! The stats given are for getting exactly that many numbers correct. 
    

  1. 235054512 in 622_614_630
    2. 

  2.  33388425 in 622_614_630
    3. 

  3.   2046800 in 622_614_630
    4. 

  4.     53550 in 622_614_630
    5. 

  5.       504 in 622_614_630
    6. 

  6.         1 in 622_614_630
    7.
To get the stats for at least that many numbers correct, add up all the results below the number in question. For instance, to get at least two numbers, you'd add up the stats for 2, 3, 4, 5, and 6 numbers correct.

thor

Update: In case anyone cares, the formula I used was choose(6,n)*choose(90-n-1,6-n)/choose(90,6) where choose(n,r) is defined as n!/(r!(n-r)!).

In reply to Re: Try your luck at Superenalotto! by thor
in thread Try your luck at Superenalotto! by bronto

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