It's not as efficient as friedo's solution, but I generally find myself writing: 
%hash1 = (%hash1, %hash2);

[download]
In other words, "hash1 is itself, plus all of hash2, using hash2's values where they conflict."
rjbs

In reply to Re: update a hash with a hash by rjbs
in thread update a hash with a hash by stupidius

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