First of all this is not really a permutation algorithm. Permutations are rearrangements of things, you want instead a list of possibilities. Which is a rather different problem. Anyways here is a cheesy answer. 
use Carp;

sub print_possib {
  my @array = @_;
  my $pat = 0; # Counter used as a bit-vector
  print "(\n";
  # A merlyn loop.
  {
    my $x = $pat;
    my @row;
    foreach my $i (@array) {
      if (2 == $i) {
        # Use the bit-vector to choose what to do now
        push @row, $x&1 ? 1 : 0;
        $x >>= 1; # Shift off the used bit
      }
      elsif (0 == $i or 1 == $i) {
        push @row, $i;
      }
      else {
        confess "Illegal value $i: Legal ones are 0, 1, and 0";
      }
    }
    if ($x) {
      # We have more bits than needed, would start repeating.
      # So end instead
      print " )\n";
      return;
    }
    else {
      print (
        ($pat ? ",\n  [ " : "( [ "), # Start or divider
        (join ", ", @row), # Row
        " ]"
      ); # Close the row
      ++$pat;
      redo;
    }
  }
}

print_possib(@ARGV);

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In reply to RE (tilly) 1 (not): Permutation algorithm? by tilly
in thread Permutation algorithm? by Shayk

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