You must name the loop variable for at least one of the loops.

for my $i ( 1 .. $#array1 ) {
    for my $j ( 1 .. $#array1 ) {
        print "$i $j\n";
    }
}

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Makeshifts last the longest.

In reply to Re: nested for loop with assumed scalars by Aristotle
in thread nested for loop with assumed scalars by Anonymous Monk

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