It looks to me like your expression is the equivilent of :

my @numbers = $aKnosId =~ m/([a-z]{2,})/g

Update I was totally wrong... sorry. Try this:

my @numbers = $aKnosId =~ m/(([a-z])(?:(?=\2)[a-z])+)/g

But then again Roy's answer is better.

May the Force be with you

In reply to Re: Finding / Replacing repetetive characters from a string in a Regular expression. by JediWizard
in thread Finding / Replacing repetetive characters from a string in a Regular expression. by nims

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