Your question almost answers itself 
my @var = (43, 60, 1..18);
# Later...
print $var[1], $var[14];

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Use an array instead of multiple, distinct variables.

turnstep is right, you don't have to initialize all the variables to zero, just create them where you need them, giving a value at that time.

runrig's code (my @array = map {0} 0..19) works fine here, as well.

In reply to Re: How can I create an array that holds number of variables with values? by Russ
in thread How can I create an array that holds number of variables with values? by Anonymous Monk

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