@x[1..3] = 1;

The left is an array slice; it's expecting a list on the right. The "list" you gave it is essentially like (1, undef, undef). So only $x[1] is getting a value here. You could write it like:

@x[1..3] = (1,1,1)

For this:

for($y=0; $y!=@x; $y++)

You should generally avoid the C-style for. You can rewrite it like this:

for my $y (0..$#x)

Also to easily view the contents of your array without having to loop, you may look into Data::Dumper.

edit: Fixed as per [id://ikegami]'s reply

In reply to Re: Initialization of arrays by chester
in thread Initialization of arrays by Anonymous Monk

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