The only comment is that it's not a HoA, it's a HoH.
The datastructure will look like this:
%HoH = ( SA => { 0009 => 1 } );
It's done that way all the time. Your second method: $HoA{$robc,$telco} will work but not in the same way (ie, it's not a hash of hashes anymore). IMHO, it's probably better to use a HoH instead of a hash with some multi-part key.
Dave
In reply to Re: multi-dimensional hash
by davido
in thread multi-dimensional hash
by fionbarr
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