print sqrt==int(sqrt)?1:0for 1..2e4;

[download]

:-)

You got away with it because perl is looking for an expression; when the thing it then sees starts with a digit, it can't be anything but a literal number. So the parser eats as many characters as can be part of a literal number and then stops. For some fun, insert an x right after the 0 and watch what happens; or try any number of underscores.

Makeshifts last the longest.

In reply to Re^2: CarTalk Puzzler by Aristotle
in thread CarTalk Puzzler by freddo411

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