hi everybody.

i have a slight problem here.

my task involve calling c from perl which inturn has perl embedded in it.

this is my c code which i call 1.c

#include <EXTERN.h> #include <perl.h> static PerlInterpreter *my_perl; int main(int argc, char **argv, char **env) { char *myargv[] ={"","Random.pl"}; PERL_SYS_INIT3(&argc,&argv,&env); my_perl=perl_alloc(); perl_construct(my_perl); PL_exit_flags |= PERL_EXIT_DESTRUCT_END; perl_parse(my_perl,NULL,argc,myargv,(char**)NULL); perl_run(my_perl); perl_destruct(my_perl); perl_free(my_perl); PERL_SYS_TERM(); }

this is my random.pl

package cryzone; print "Hello"; print " i am in random"; print $cryzone::a; 1;

this is my file test.pl from which i call 1.exe

use cryzone; $cryzone::a=1; print $cryzone::a; system("1.exe"); $cryzone::a=2; print $cryzone::a;

and this is my package cryzone

package cryzone; $a=0; 1;

on running i am never able to access $cryzone::a inside random.pl even though ihave declared it as belonging to cryzone.

how can this be solved.

the output is

1Hello i am in random2

whereas the desired output is

1Hello i am in random12

please help me.

Edited by planetscape - added code tags around output


In reply to embedding perl by rocketboy

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