If you'd bother to read perlre it quite clearly states that the only thing the /s modifier does is change the meaning of a "." to also match a \n character. That's in no way going to affect performance meaningfully.

In reply to Re: Which is the efficient pattern matching modifiers (s///g; or s///gs;)? by Fletch
in thread Which is the efficient pattern matching modifiers (s///g; or s///gs;)? by perlsen

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