Just operate on $_[0] directly, as it aliases the parameter. 

#define the sub
sub strip_space
{
    # remove whitespace and retrn true on success
    $_[0] =~ s/\s+//g;
    return 1;
}

[download]

-xdg

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In reply to Re: get a reference implicitly within a subroutine call? by xdg
in thread get a reference implicitly within a subroutine call? by Anonymous Monk

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