Please tell me how is the matching done?

The m#/([^/]+)$# matches a string of one or more non-slash characters at the end of a single-line string. (1) One or more is implied by +. (2) non-slash is implied by [^/]. (3) at the end of the string is implied by $. So when you feed the regex with $dir = "/exp/01jehandel/userinput/runwhennewfile", it matches runwhennewfile as you said.

Also what difference does putting brackets '()' for $thisj in its assignment statement makes?

The '()' capture the enclosed regex piece into the first group, $1. As a list assignment is being done, in ($thisj) = $dir =~ ..., that means the matching groups are returned to the left side value. But there's only one group here and $thisj will get its contents.

what is '#' doing here?

As the regex uses literal slashes (/), another delimiter was chosen (in the case, #). That what means m# ... #. Otherwise, it should have been written as /\/([^\/]+)$/ (which is hard to read).

You may learn more at perlretut and perlre.

In reply to Re: Perl Regular Exp by ferreira
in thread Perl Regular Exp by Nalina

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