i don't have access to 5.6 at the moment and so cannot investigate your question, but just as a matter of curiosity, why use the expression  return @rv[ 0 .. $#rv ]; when it seems to me it will return exactly the same thing as  return @rv; and when the latter expression does not involve the behavior of the  .. range operator in the case where the terminal value is less than the initial value, i.e.,  0 .. -1 in the case of  $#rv when the array  @rv is empty?

(you haven't been messing with  $[ have you?)

In reply to Re: regexp list return 5.6 vs 5.8 by Anonymous Monk
in thread regexp list return 5.6 vs 5.8 by Sixtease

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