Nah, use unpack at will.

You will have to pad them missing values: 

$a = "\001"; #just another hex string
$a = ("\000" x (4-length($a))).$a; #Zero pad that string
print unpack 'L', $a; #Hey, that's one!

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Jeroen
"We are not alone"(FZ)

In reply to Re:{3} Constructing 32-bit hexadecimal integers by jeroenes
in thread Constructing 32-bit hexadecimal integers by donfreenut

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