I could only guess that it would be:     $mystery = ($a < $b) && ($b < $c) && ($c < $d) && ($d < $f); As in, for any:     A x B y C Where 'x' and 'y' are one of ('>','>=','<','<='), then the equivalent would be:     (A x B) && (B y C) Which would also hold true for: 
    A < B >= C  -> (A < B) && (B >= C)
    A > B < C   -> (A > B) && (B < C)

[download]
And so forth.

In reply to Re^3: Why not support this syntax? by tadman
in thread Why not support this syntax? by MeowChow

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