I want to get $path from $target. How I do it in one regexp?

# How to optimize?

Those are two different questions, and are likely to have different answers. I would leave it as is, but if you insist on using one regexp, I guess (haven't tried it), something like: 
$path =~ s/(?:[^/]*\?.*$)|(?:[^/]+$)/;

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In reply to Re: How to replace in one regexp by JavaFan
in thread How to replace in one regexp by appleii

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