Are you being dense on purpose??
Commutativity Breakage != Commutative Breakage
(which would be the answer to your question #1)
Commutativity Breakage == Breakage of the Commutativity
i. e.,
the commutativity (Of the
~~ operator)
is broken, or IOW,
is not working anymore.
And,
because the commutativity is not working anymore, code references are no longer treated specially. (They were treated specially before, because the
~~ operator was commutative). Easier to parse now?
[]s, HTH, Massa (κς,πμ,πλ)
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