Re^10: Perl 5.11.0 now available

Are you being dense on purpose??

Commutativity Breakage != Commutative Breakage
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(which would be the answer to your question #1)

Commutativity Breakage == Breakage of the Commutativity
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i. e., the commutativity (Of the ~~ operator) is broken, or IOW, is not working anymore. And, because the commutativity is not working anymore, code references are no longer treated specially. (They were treated specially before, because the ~~ operator was commutative). Easier to parse now?

[]s, HTH, Massa (κς,πμ,πλ)

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Re^11: Perl 5.11.0 now available by Anonymous Monk on Oct 04, 2009 at 13:36 UTC
Commutativity Breakage != Commutative Breakage As adverbs are often being used to clarfiy "in what way?", commutatively broken (as BU said) could well mean "the operator is broken with respect to its commutativity", and not "Commutative Breakage", which doesn't make sense in the context.	[reply]