( And I mean, seriously... where the #$!@& is shift output going?? Is its scope only in () ??? )

Actually, it's scope is the whole while loop. For instance..

for my $foo (@wibble) {
   print $foo;
}

[download]

Oh, and $_ is global, as mentioned above (said Pileofrog as though he already knew that...) so the scope won't matter.

UpdateD'oh! Removed stupid '=' sign. Thanks moritz.

In reply to Re: using shift and $_ in loop by pileofrogs
in thread using shift and $_ in loop by leocharre

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