The simplest way would be to print: 
print scalar(localtime(time));

[download]

Although you could format it by getting all the elements individually: 
@elements = localtime(time);

[download]

You can easily find a reference that will tell you what each element is, just remember that months, days of year, other data is 0 based - meaning January is 0, Feb is 1, .. Dec is 11.

In reply to Re: Getting the date of today as a number (was: Date question) by dsdisc
in thread Getting the date of today as a number (was: Date question) by Anonymous Monk

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