Yes, the [@array] construct builds an array ref with a
copy of the array --- But, the code in question uses the x operator
to replicate a list of those references, and they will all be the same
reference. Witness:
my @list = (3,2,1);
my @refs = ([@list]) x @list;
print "@refs\n";
__END__
which prints:
ARRAY(0x80f3764) ARRAY(0x80f3764) ARRAY(0x80f3764)
Those are not references to the original array, they are all
references to the same anonymous array that holds a copy of
the original.
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