Not quite. 
() = 'abc' =~ /(?<a>a)|(?<f>f)/ and do {say for keys %-};
__END__
a
f

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%- will have a key for every named capture in the pattern, whether that capture was involved in the match or not.

In reply to Re^5: Named Captures by JavaFan
in thread Named Captures by BrowserUk

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