..while this only prints out the "test new line" one for some reason?

while ($test =~ s{$re}{}ge) {
    print "BLA: $1 \n";
}

That is because s///g ignores context and just does all the replacements at once leaving the last match in $1.

But m//g in scalar context will iterate through each match every time it is called in scalar context so that in a while loop $1 will contain each match in turn.

In reply to Re^5: Regex question - negatives by jwkrahn
in thread Regex question - negatives by ultranerds

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