Hey toolic, thanks for the reply.

Duhh haha... I guess I had a brain fart on that one..! lol thanks.

I was just using the printing as an example. What I'm reallying trying to do is to add 8 consecutive values from the hash and place that summed value in an array.

Using the same hash, would this be what I should do?
my @sum_values;
my $x = 0;

foreach my $key ( keys %ifSpeeds )
{
    if ($counter <= 8) {
        $sum_values[$x] += $ifSpeeds{ $key };
        $counter++;
    } else { 
        $x++;
        $sum_values[$x] = $ifSpeeds{ $key };
        $counter = 1;
    }
}

for (my $x = 0; $x <= $#sum_values; $x++)
{
    print "$x) $sum_values\n";
}

[download]

The final result (given the hash with 32 elements) would be that the array would contains 4 values, which include the following:
   [0] --> (sum of Gi3/1 to Gi3/8)
   [1] --> (sum of Gi3/9 to Gi3/16)
   [2] --> (sum of Gi3/17 to Gi3/24)
   [3] --> (sum of Gi3/25 to Gi3/32)

[download]
Does all that look correct to you?


Thanks Again,
Matt


In reply to Re^2: Looping Over Hash Skips an Element? by mmartin
in thread Looping Over Hash Skips an Element? by mmartin

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