It cannot be correct. Have you actually tried this? Considering that any number is divisible by 1, isPrime will return 1 for each number. A fix is easy, have $i start at 2.

But then you are still far from being efficient. There's no need to loop to $num/2, you can stop at sqrt($num). There's no need to test even numbers (except 2). And there's no need to continue once you've found a divisor.

In reply to Re: is it prime? by JavaFan
in thread is it prime? by Anonymous Monk

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