in reply to Perl Problems with Digit Precision Changing on the Printf Statement

It works for me. The second one has a trailing newline that the first doesn't have, of course. You could also interpolate $digitprecision right in the format string: 
printf STDOUT ("\n%${digitprecision}s\n" , $value);

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Include the output you're getting from the two lines so we can see the problem.

I do find it a little odd, talking about "digit precision" when you're telling printf that you're printing a string.

We're not really tightening our belts, it just feels that way because we're getting fatter.
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Re^2: Perl Problems with Digit Precision Changing on the Printf Statement
by EchoAngel (Pilgrim) on Jun 24, 2004 at 17:31 UTC
    I want the output from 
    my $value = "0.03443762";

$digitprecision = 20;

printf STDOUT ("\n%20s\n", $newvalue);

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    I want the this printf statement to print exactly as it is 
    output
          0.03443762

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    so how do i program this using $digitprecision = 20; I need to control the number of spacing using a variable
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[d/l]
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      Just like you did, or like I responded: 
      # You did this, and it works:
printf STDOUT ("\n%" . $digitprecision . "s\n", $newvalue);
# I suggested this, and it works, too:
printf STDOUT ("\n%${digitprecision}s\n", $newvalue);

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      We're not really tightening our belts, it just feels that way because we're getting fatter.
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[d/l]
        thanks!!!!!!!
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