Re^2: Perl Problems with Digit Precision Changing on the Printf Statement

I want the output from

my $value = "0.03443762";

$digitprecision = 20;

printf STDOUT ("\n%20s\n", $newvalue);
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I want the this printf statement to print exactly as it is

output
          0.03443762
[download]

so how do i program this using $digitprecision = 20; I need to control the number of spacing using a variable

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Re^3: Perl Problems with Digit Precision Changing on the Printf Statement by Roy Johnson (Monsignor) on Jun 24, 2004 at 17:42 UTC
Just like you did, or like I responded: `# You did this, and it works: printf STDOUT ("\n%" . $digitprecision . "s\n", $newvalue); # I suggested this, and it works, too: printf STDOUT ("\n%${digitprecision}s\n", $newvalue);` [download] We're not really tightening our belts, it just feels that way because we're getting fatter.	[reply] [d/l]
Re^4: Perl Problems with Digit Precision Changing on the Printf Statement by EchoAngel (Pilgrim) on Jun 24, 2004 at 18:51 UTC
thanks!!!!!!!	[reply]