in reply to Re: hash to text
in thread hash to text

btw, why when i change the code to :
my %h = ( word1 =>[2,3], word2 =>[1,3], word3 =>[1,2] ); $h{word1} = [ $h{word2},$h{word3}]; $h{word2} = [ $h{word1},$h{word3}]; $h{word3} = [ $h{word1},$h{word2}]; print @{ @{ $h{'word3'} }[0] }[0], "\n";

it gives me out the output : ARRAY(0x8064e68)

And, how can i see this in normal now ?

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Re^3: hash to text
by Velaki (Chaplain) on Aug 14, 2004 at 22:02 UTC

    Let's look at your code with some hand calculations thrown in for fun.

    #!/usr/bin/perl my %h = ( word1 =>[2,3], word2 =>[1,3], word3 =>[1,2] ); $h{word1} = [ $h{word2},$h{word3}]; # [[1,3],[1,2]] $h{word2} = [ $h{word1},$h{word3}]; # [[[1,3],[1,2]],[1,2]] $h{word3} = [ $h{word1},$h{word2}]; # [[[1,3],[1,2]],[[[1,3],[1,2]],[1 +,2]]] print @{ @{ $h{'word3'} }[0] }[0], "\n";

    If you look at the data above, you'll see that you're dereferencing the structure twice. Well, when looking at the zeroeth element, you'll notice that your print statement above gives a reference to an array, specifically [1,3].

    To print it, you will need to deref it one more time.

    print @{ @{ $h{'word3'} }[0] }[0]->[0], "\n"; # prints "1" print @{ @{ $h{'word3'} }[0] }[0]->[1], "\n"; # prints "3"

    When in doubt, walk through your data by hand; use Data::Dumper; inspect things.

    Hope this helps,

    -v
    "Perl. There is no substitute."