in reply to Re^2: hash to text
in thread hash to text

Let's look at your code with some hand calculations thrown in for fun.

#!/usr/bin/perl my %h = ( word1 =>[2,3], word2 =>[1,3], word3 =>[1,2] ); $h{word1} = [ $h{word2},$h{word3}]; # [[1,3],[1,2]] $h{word2} = [ $h{word1},$h{word3}]; # [[[1,3],[1,2]],[1,2]] $h{word3} = [ $h{word1},$h{word2}]; # [[[1,3],[1,2]],[[[1,3],[1,2]],[1 +,2]]] print @{ @{ $h{'word3'} }[0] }[0], "\n";

If you look at the data above, you'll see that you're dereferencing the structure twice. Well, when looking at the zeroeth element, you'll notice that your print statement above gives a reference to an array, specifically [1,3].

To print it, you will need to deref it one more time.

print @{ @{ $h{'word3'} }[0] }[0]->[0], "\n"; # prints "1" print @{ @{ $h{'word3'} }[0] }[0]->[1], "\n"; # prints "3"

When in doubt, walk through your data by hand; use Data::Dumper; inspect things.

Hope this helps,

-v
"Perl. There is no substitute."