Re^2: Best way to make sure a number is an even multiple of another?

Yeah, thats it. Thanks and ++ merlyn. I knew it was possible, I just couldn't see past the damn if. :-)

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demerphq

_{First they ignore you, then they laugh at you, then they fight you, then you win.

-- Gandhi

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Comment on Re^2: Best way to make sure a number is an even multiple of another?

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Re^3: Best way to make sure a number is an even multiple of another? by Arunbear (Prior) on Oct 21, 2004 at 14:01 UTC
I may have misunderstood this, but with $n = 19 and $m = 3, fix gives 21 which is not an even multiple of 3. Why not just use `$m * $n * 2` ?	[reply] [d/l]
Re^4: Best way to make sure a number is an even multiple of another? by husker (Chaplain) on Oct 21, 2004 at 14:13 UTC
7 * 3 = 21?	[reply]
Re^5: Best way to make sure a number is an even multiple of another? by Arunbear (Prior) on Oct 21, 2004 at 14:23 UTC
7 is not an even number (i.e. - not divisible by 2)	[reply]
Re^6: Best way to make sure a number is an even multiple of another? by thor (Priest) on Oct 21, 2004 at 14:32 UTC
Re^6: Best way to make sure a number is an even multiple of another? by grinder (Bishop) on Oct 21, 2004 at 14:33 UTC
Re^6: Best way to make sure a number is an even multiple of another? by husker (Chaplain) on Oct 21, 2004 at 14:33 UTC