Re: Find if a number is a multiple of a number.

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Re^2: Find if a number is a multiple of a number. by Baratski (Acolyte) on Mar 02, 2005 at 12:50 UTC
Reply to all. Sweeeet! Works great! And much, much faster than my code. Thanks!	[reply]
Re^2: Find if a number is a multiple of a number. by blazar (Canon) on Mar 03, 2005 at 07:41 UTC
use % for positive integer values. What does make you think that the use `%` of is limited to positive integers? `$ perl -le 'print for map $_%-3, -18..-15' 0 -2 -1 0` [download]	[reply] [d/l] [select]
Re^3: Find if a number is a multiple of a number. by borisz (Canon) on Mar 03, 2005 at 10:26 UTC
The docs: from perlop Binary "%" computes the modulus of two numbers.Given integer operands $a and $b: If $b is positive, then "$a % $b" is $a minus the largest multiple of $b that is not greater than $a. If $b is negative then "$a % $b" is $a minus the smallest multiple of $b that is not less tha +n $a (i.e. the result will be less than or equal to zero). Note that when "use integer" is in scope "%" gives you direct access to the mod- ulus operator as implemented by your C compiler. This operator is not as well defined for negative operands, but it will execute faster. [download] Boris	[reply] [d/l]
Re^4: Find if a number is a multiple of a number. by blazar (Canon) on Mar 03, 2005 at 13:59 UTC
Binary "%" computes the modulus of two numbers.Given integer operands $a and $b: If $b is positive, then "$a % $b" is $a minus the largest multiple of $b that is not greater than $a. If $b is negative then "$a % $b" is $a minus the smallest multiple of $b that is not less than And... so what? $a (i.e. the result will be less than or equal to zero). Note that when "use integer" is in scope "%" gives you direct access to the mod- ulus operator as implemented by your C compiler. This operator is not as well defined for negative operands, but it will execute faster. Is this the particular point on which you meant to draw the attention? If so, then it actually is a good point, however IMHO it belongs more to the realm of side notes...	[reply]