Re: Implicit split to @

If you want to do it like that for whatever reason you may have (rather than using length as others have suggested) you will need to use a temporary array:

my $sa = do { my @tmp = split //, $vartable{$a} };
[download]

The do block is there just to reduce the scope of the temporary array - you can do away with it if you want to predeclare the array.

Of course I would recommend that you do this with length

/J\

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Re^2: Implicit split to @_ by ysth (Canon) on Apr 14, 2005 at 22:30 UTC
`my $sa = () = split //, $vartable{$a}, -1` also does the trick. (Update: added necessary -1.)	[reply] [d/l]
Re^3: Implicit split to @_ by gellyfish (Monsignor) on Apr 15, 2005 at 10:12 UTC
Er are you sure: `perl -e 'my $sa = () = split //,"foo"; print $sa'` [download] vs `perl -e 'my $sa = do {my @tmp = split //,"foo"}; print $sa'` [download] split() is outwitting us here - it sees the empty list and optimizes accordingly. /J\	[reply] [d/l] [select]
Re^4: Implicit split to @_ by Anonymous Monk on Apr 15, 2005 at 15:12 UTC
`perl -e 'my $sa = () = split //,"foo",-1; print $sa'`	[reply] [d/l]