Re: Regular Expression Help

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Re^2: Regular Expression Help by Anonymous Monk on Jun 28, 2005 at 17:53 UTC
Hi interesting, can you give me an explaination on this code? Thanks!	[reply]
Re^3: Regular Expression Help by Transient (Hermit) on Jun 28, 2005 at 17:58 UTC
Sure! Basically if you take where we started : `$u = ('0' x (6-length($u))).$u;` we can break this up into multiple statements: `$length_of_u = length($u); # how long is this string? $how_many_characters_short = 6-$length_of_u; # how far are we from ha +ving 6 characters? $padding = '0' x $how_many_characters_short; # this will give us as ma +ny 0's as $how_many_characters_short is long (e.g. if it is 4 - it gi +ves us '0000') $u = $padding.$u; # concatenate them together... finished!` [download] HTH!	[reply] [d/l] [select]
Re^4: Regular Expression Help by Anonymous Monk on Jun 28, 2005 at 18:01 UTC
Thank you all for the big HELP!!!!	[reply]