Re^6: Declare and slice-initialize hash in one statement?

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Re^7: Declare and slice-initialize hash in one statement? by BrowserUk (Patriarch) on Oct 27, 2005 at 17:59 UTC
Yeah, just too darn subtle. `sub x (\@\@) { print "@_" } @_ = qw[ some random junk retained from the current level of call ]; @a = 1..10; @b='a'..'g'; x @a, @b; ARRAY(0x1961458) ARRAY(0x196156c) &x( @a, @b ); 1 2 3 4 5 6 7 8 9 10 a b c d e f g &x, @a, @b; some random junk retained from the current level of call` [download] Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal? "Science is about questioning the status quo. Questioning authority". In the absence of evidence, opinion is indistinguishable from prejudice.	[reply] [d/l]
Re^8: Declare and slice-initialize hash in one statement? by BUU (Prior) on Oct 27, 2005 at 20:23 UTC
You realize you aren't passing any arguments to &x in the last example?	[reply]
Re^9: Declare and slice-initialize hash in one statement? by BrowserUk (Patriarch) on Oct 27, 2005 at 20:50 UTC
Yes, but it is oh so subtle isn't it? Or rather, I am, but not what was intended. Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal? "Science is about questioning the status quo. Questioning authority". In the absence of evidence, opinion is indistinguishable from prejudice.	[reply] [d/l]