Re^7: Declare and slice-initialize hash in one statement?

Yeah, just too darn subtle.

sub x (\@\@) { print "@_" }

@_ = qw[ some random junk retained from the current level of call ];
@a = 1..10; @b='a'..'g';

x @a, @b;
ARRAY(0x1961458) ARRAY(0x196156c)

&x( @a, @b );
1 2 3 4 5 6 7 8 9 10 a b c d e f g

&x, @a, @b;
some random junk retained from the current level of call
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Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.

Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal?

"Science is about questioning the status quo. Questioning authority".

In the absence of evidence, opinion is indistinguishable from prejudice.

Comment on Re^7: Declare and slice-initialize hash in one statement? Download Code

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Re^8: Declare and slice-initialize hash in one statement? by BUU (Prior) on Oct 27, 2005 at 20:23 UTC
You realize you aren't passing any arguments to &x in the last example?	[reply]
Re^9: Declare and slice-initialize hash in one statement? by BrowserUk (Patriarch) on Oct 27, 2005 at 20:50 UTC
Yes, but it is oh so subtle isn't it? Or rather, I am, but not what was intended. Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error. Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal? "Science is about questioning the status quo. Questioning authority". In the absence of evidence, opinion is indistinguishable from prejudice.	[reply] [d/l]